Rhodium Ionization Energy

The Rhodium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Rhodium.
Rh -> Rh⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Rhodium is:
Rh^N+ -> Rh^(N+1)+ + e^-

Rh -> Rh¹⁺ = 720 kJ/mol = 172.25 Kcal/mol
Rh¹⁺ -> Rh²⁺ = 1744 kJ/mol = 417.22 Kcal/mol
Rh²⁺ -> Rh³⁺ = 2997 kJ/mol = 716.99 Kcal/mol
Rh³⁺ -> Rh⁴⁺ = 4400 kJ/mol = 1052.63 Kcal/mol
Rh⁴⁺ -> Rh⁵⁺ = 6500 kJ/mol = 1555.02 Kcal/mol
Rh⁵⁺ -> Rh⁶⁺ = 8200 kJ/mol = 1961.72 Kcal/mol
Rh⁶⁺ -> Rh⁷⁺ = 10100 kJ/mol = 2416.27 Kcal/mol
Rh⁷⁺ -> Rh⁸⁺ = 12200 kJ/mol = 2918.66 Kcal/mol
Rh⁸⁺ -> Rh⁹⁺ = 14200 kJ/mol = 3397.13 Kcal/mol
Rh⁹⁺ -> Rh¹⁰⁺ = 22000 kJ/mol = 5263.16 Kcal/mol