The Rhodium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Rhodium.
Rh -> Rh+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Rhodium is:
RhN+ -> Rh(N+1)+ + e-
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Rh -> Rh1+ = 720 kJ/mol = 172.25 Kcal/mol
\nRh1+ -> Rh2+ = 1744 kJ/mol = 417.22 Kcal/mol
\nRh2+ -> Rh3+ = 2997 kJ/mol = 716.99 Kcal/mol
\nRh3+ -> Rh4+ = 4400 kJ/mol = 1052.63 Kcal/mol
\nRh4+ -> Rh5+ = 6500 kJ/mol = 1555.02 Kcal/mol
\nRh5+ -> Rh6+ = 8200 kJ/mol = 1961.72 Kcal/mol
\nRh6+ -> Rh7+ = 10100 kJ/mol = 2416.27 Kcal/mol
\nRh7+ -> Rh8+ = 12200 kJ/mol = 2918.66 Kcal/mol
\nRh8+ -> Rh9+ = 14200 kJ/mol = 3397.13 Kcal/mol
\nRh9+ -> Rh10+ = 22000 kJ/mol = 5263.16 Kcal/mol
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